[Glitch] Fix possible duplicate statuses in timelines in some edge cases
Port dd4c156f33
to glitch-soc
Signed-off-by: Claire <claire.github-309c@sitedethib.com>
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b368c75029
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e2f4bafc13
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@ -16,7 +16,7 @@ import {
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ACCOUNT_MUTE_SUCCESS,
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ACCOUNT_UNFOLLOW_SUCCESS,
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} from 'flavours/glitch/actions/accounts';
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import { Map as ImmutableMap, List as ImmutableList, fromJS } from 'immutable';
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import { Map as ImmutableMap, List as ImmutableList, OrderedSet as ImmutableOrderedSet, fromJS } from 'immutable';
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import compareId from 'flavours/glitch/util/compare_id';
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const initialState = ImmutableMap();
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@ -32,6 +32,13 @@ const initialTimeline = ImmutableMap({
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});
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const expandNormalizedTimeline = (state, timeline, statuses, next, isPartial, isLoadingRecent, usePendingItems) => {
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// This method is pretty tricky because:
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// - existing items in the timeline might be out of order
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// - the existing timeline may have gaps, most often explicitly noted with a `null` item
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// - ideally, we don't want it to reorder existing items of the timeline
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// - `statuses` may include items that are already included in the timeline
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// - this function can be called either to fill in a gap, or load newer items
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return state.update(timeline, initialTimeline, map => map.withMutations(mMap => {
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mMap.set('isLoading', false);
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mMap.set('isPartial', isPartial);
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@ -45,15 +52,34 @@ const expandNormalizedTimeline = (state, timeline, statuses, next, isPartial, is
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mMap.update(usePendingItems ? 'pendingItems' : 'items', ImmutableList(), oldIds => {
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const newIds = statuses.map(status => status.get('id'));
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const lastIndex = oldIds.findLastIndex(id => id !== null && compareId(id, newIds.last()) >= 0) + 1;
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const firstIndex = oldIds.take(lastIndex).findLastIndex(id => id !== null && compareId(id, newIds.first()) > 0);
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if (firstIndex < 0) {
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return (isPartial ? newIds.unshift(null) : newIds).concat(oldIds.skip(lastIndex));
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// Now this gets tricky, as we don't necessarily know for sure where the gap to fill is
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// and some items in the timeline may not be properly ordered.
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// However, we know that `newIds.last()` is the oldest item that was requested and that
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// there is no “hole” between `newIds.last()` and `newIds.first()`.
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// First, find the furthest (if properly sorted, oldest) item in the timeline that is
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// newer than the oldest fetched one, as it's most likely that it delimits the gap.
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// Start the gap *after* that item.
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const lastIndex = oldIds.findLastIndex(id => id !== null && compareId(id, newIds.last()) >= 0) + 1;
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// Then, try to find the furthest (if properly sorted, oldest) item in the timeline that
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// is newer than the most recent fetched one, as it delimits a section comprised of only
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// items present in `newIds` (or that were deleted from the server, so should be removed
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// anyway).
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// Stop the gap *after* that item.
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const firstIndex = oldIds.take(lastIndex).findLastIndex(id => id !== null && compareId(id, newIds.first()) > 0) + 1;
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// Make sure we aren't inserting duplicates
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let insertedIds = ImmutableOrderedSet(newIds).subtract(oldIds.take(firstIndex), oldIds.skip(lastIndex)).toList();
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// Finally, insert a gap marker if the data is marked as partial by the server
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if (isPartial && (firstIndex === 0 || oldIds.get(firstIndex - 1) !== null)) {
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insertedIds = insertedIds.unshift(null);
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}
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return oldIds.take(firstIndex + 1).concat(
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isPartial && oldIds.get(firstIndex) !== null ? newIds.unshift(null) : newIds,
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return oldIds.take(firstIndex).concat(
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insertedIds,
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oldIds.skip(lastIndex),
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);
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});
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